검색 조건 쿼리

기본 검색 쿼리

@Test
    public void search() {
        Member findMember = queryFactory
                .selectFrom(member)
                .where(member.username.eq("member1").and(member.age.eq(10)))
                .fetchOne();

        assertThat(findMember.getUsername()).isEqualTo("member1");
    }

검색 조건은 .and() , . or() 를 메서드 체인으로 연결할 수 있다.

 

참고: select , from 을 selectFrom 으로 합칠 수 있음

 

 

 

JPQL이 제공하는 모든 검색 조건 제공

member.username.eq("member1") // username = 'member1'
member.username.ne("member1") //username != 'member1'
member.username.eq("member1").not() // username != 'member1'
member.username.isNotNull() //이름이 is not null
member.age.in(10, 20) // age in (10,20)
member.age.notIn(10, 20) // age not in (10, 20)
member.age.between(10,30) //between 10, 30
member.age.goe(30) // age >= 30
member.age.gt(30) // age > 30
member.age.loe(30) // age <= 30
member.age.lt(30) // age < 30
member.username.like("member%") //like 검색
member.username.contains("member") // like ‘%member%’ 검색
member.username.startsWith("member") //like ‘member%’ 검색
...

 

 

AND 조건을 파라미터로 처리

@Test
    public void searchAndParam() {
        Member findMember = queryFactory
                .selectFrom(member)
                .where(member.username.eq("member1"),
                        member.age.eq(10))
                .fetchOne();

        assertThat(findMember.getUsername()).isEqualTo("member1");
    }

where() 에 파라미터로 검색조건을 추가하면 AND 조건이 추가됨
이 경우 null 값은 무시 메서드 추출을 활용해서 동적 쿼리를 깔끔하게 만들 수 있음 뒤에서 설명

 

 

 

 

출처 : 김영한 JPA 스프링 데이터 강의